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ThreeExcedances ​

Positions with p(i) = i + 3.

✓ checked against that system · ! checked, with disagreements (hover a chip)FindStatSt000649via Permutation✓
ThreeExcedances(p)Positions with p(i) = i + 3.
Typed signatures
TypePackageApplies
(permutation) -> numbercombinatoricsalways

Domain: Permutation statistics

Details
  • Defined over Permutation as an expression in _x, evaluated by compute-engine — the definition IS the implementation.
  • Takes a Permutation and nothing else — it reads values against their positions, or walks the orbits, so it needs the bijection. Applying it to a bare list is a type error, not a wrong answer.

Definition

Epsil, as the implementation runs it.

on Permutation, over _x

0 if Length(_x) < 1 else Count(Filter(
                                       Range(1, Length(_x)),
                                       Function(_x[i] == i + 3, i),
                                     ))

Examples

Basic #

the one-line word 312312

live ↗
InThreeExcedances(Permutation⁡([3,1,2]))\mathrm{ThreeExcedances}({\operatorname{Permutation}}([3, 1, 2]))Out00

the one-line word 24132413

live ↗
InThreeExcedances(Permutation⁡([2,4,1,3]))\mathrm{ThreeExcedances}({\operatorname{Permutation}}([2, 4, 1, 3]))Out00
Properties #

FindStat's value for [1,2]

live ↗
InCombinatorialStat(Permutation⁡([1,2]),ThreeExcedances)\mathrm{CombinatorialStat}({\operatorname{Permutation}}([1, 2]), \text{ThreeExcedances})Out00

Known value · FindStat St000649

FindStat's value for [2,1]

live ↗
InCombinatorialStat(Permutation⁡([2,1]),ThreeExcedances)\mathrm{CombinatorialStat}({\operatorname{Permutation}}([2, 1]), \text{ThreeExcedances})Out00

Known value · FindStat St000649

FindStat's value for [1,2,3]

live ↗
InCombinatorialStat(Permutation⁡([1,2,3]),ThreeExcedances)\mathrm{CombinatorialStat}({\operatorname{Permutation}}([1, 2, 3]), \text{ThreeExcedances})Out00

Known value · FindStat St000649

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